The average salary (in thousands of dollars) at a certain company for the first ten years of its existence can be approximated by the model S = 0.2t2 + 2.1t + 32.5, 0 t 10. How many years did it take for the average salary to reach $41,000? Round the answer to the nearest hundredth of a year.

3.12years

Step-by-step explanation:

Given the average salary (in thousands of dollars) at a certain company for the first ten years of its existence approximated by the model

S = 0.2t² + 2.1t + 32.5,

To calculate the years it take for the average salary to reach $41,000, we will substitute s = 41000 and calculate for t

41 = 0.2t² + 2.1t + 32.5

Multiply through by 10

410 = 2t²+21t+325

2t²+21t+325 = 410

2t²+21t+325-410= 0

2t²+21t-85 = 0

On factorizing:

t = -21±√21²-4(2)(-85)/2(2)

t = -21±√441+680/4

t = -21±√1121/4

t = -21+33.48/4

t = 12.48/4

t = 3.12

Hence the number of years to average hundredth of a year is 3.12years

answer: i believe the answer is e

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.