Chloe is trying to find three consecutive, positive integers such that six times the largest is equal to the twice sum of the two smaller integers. Set up an equation that models the numbers chloe is trying to find

The equation is 6 × (x + 1) = 2 × (x + x + 1)

The integers are negative (-5, -4, -3)

Step-by-step explanation:

The numbers Chloe is trying to find = Three consecutive positive integers

The nature of the numbers Chloe is trying to find = The product of 6 and the largest of the three numbers = 2 × The sum of the two smaller integers

To set up the equation, we proceed as follows;

Let the three numbers be x, x + 1, x + 2

Therefore, the equation is given as follows;

6 × (x + 1) = 2 × (x + x + 1)

We simplify, to get;

6·x + 12 = 2·x + 2·x + 2

6·x + 12 = 4·x + 2

6·x + 4·x  = 2 - 12

2·x  = -10

x = -10/2 = -5

The integers are;

-5, -4, -3

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