Find the equation of a line that passes through the points (6,4) and (8,2). Leave your answer in the form y=mx+c

y = -x + 10

Step-by-step explanation:

The equation can be written in the form

y= mx + c

where m is slope and c is y-intercept

Slope m;

m = y2-y1/x2-x1 = (2-4)/(8-6) = -2/2 = -1

So the equation is now

y = -x + c

we need to get the y-intercept

To get this we can use any of the given points

4 = -6 + c

c = 4 + 6 = 10

So the relationship will be;

y = -x + 10

step-by-step explanation:

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