PLEASE ANSWER PART A AND B Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and cos ∠X = 2 and 5 tenths over 5 and 59 hundredths.

Part A: Use complete sentences to explain the special relationship between the trigonometric ratios of triangles XYZ and ABC. You must show all work and calculations to receive full credit. (5 points)

Part B: Explain how to find the measures of segments AC and AB. You must show all work and calculations to receive full credit. (5 points)

As for the angles of both triangles; they're the same. The sides are 1:2.

I'm giving you formulas that are labeled: side a shortest

                                                            "    b mid length

                                                            "    c hypotenuse

                                                         angle α(alpha)  opposite side a

                                                            "     β(beta)          "       "    b

                                                            "     γ(gamma)     "       "     c

A major formula for rt triangles is: a^2+b^2=c^2.

*Another is: a/sinα=b/sinβ=c/sinγ.

Remember α+β+γ=180°.

As for sides a&b use the above formula.  As for <ACB; the angle is γ which is a rt <.

Given: tan<x=5/2+1/2=6/2=3atan=71.565°=β. So α=18.44°. γ= rt angle.

To get the sides use the formulas at *.

show us the graphs dude

step-by-step explanation:

boxplot