Suppose the growth of a tumor with radius r(t) (t = time in weeks) is described by the equation r′(t)=k1t+n(t) where n(t)=2k2, k1=1, and k2=1.5. If the tumor's initial radius is r(0)=0.25 cm, which of the following is the closest to the time it would take for the tumor to reach a radius of 15 cm?

but which class are u may know that first

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: