Mathematics, 24.08.2019 05:30, makaylahunt

Part a: if (6^2)^x = 1, the value of x is 0. the reason for it being 0 is because anything to the power of 0 equals 1. part b: if (6^0)^x = 1, then the value of x here is also

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Part a: if (6^2)^x = 1, the value of x is 0. the reason for it being 0 is because anything to the p...

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