PLEASE HELP ME AND MY DAD ARE STUMPED The following is an incorrect flowchart proving that point L, lying on line LM which is a perpendicular bisector of segment JK, is equidistant from points J and K:

What is the error in this flowchart?

1) JL and KL are equal in length, according to the definition of a midpoint.
2)An arrow is missing between ∠LNK = 90° and ∠LNJ = 90° and ∠LNK ≅ ∠LNJ.
3)An arrow is missing between the given statement and ∠LNK ≅ ∠LNJ.
4)Triangles JNL and KNL are congruent by the Angle-Angle Side (AAS) Postulate.

Point L is equidistant from endpoints J and K, not J and N.

your welcome

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3