A square is drawn on the coordinate plane. The endpoints of one of its sides are located at (-1,4), and (-1,-2). What are the endpoints of its sides and the perimeter?

Remaining end points are; (-7, 4) and (-7, - 2)

Perimeter = 24

Step-by-step explanation:

We are given one of it's sides as;

located at (-1,4), and (-1,-2)

We can see that the x - value in both points are -1. Thus, the length of this side would be the difference of the y - value. Thus, side length = 4 - (-2) = 6

Since it is a square, the four sides will be the same length.

Now, the horizontal side perpendicular to (-1,4) have it's y value as 4 too.

Thus, the coordinate is (x, 4). Since a side is 6. Then;

(-1) - x = 6

-x = 6 + 1

x = -7

3rd coordinate is (-7, 4)

Now, the horizontal side perpendicular to (-1,-2) will have it's y value as -2 too.

Thus, coordinate is (x, -2)

Since a side is 6. Then;

(-1) - x = 6

-x = 6 + 1

x = -7

4th coordinate = (-7, -2)

Perimeter of a square = 4 × side length

Perimeter = 4 × 6 = 24

answer: slight chance that it will happen

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.