Rachelle has $4.75 in nickels, dimes, and quarters. If she has four more nickels than dimes and twice as many quarters as dimes, how many of each kind of coin does she have?

Given:

Total amount Rachelle has = $4.75

She has four more nickels than dimes and twice as many quarters as dimes.

To find:

The number of each kind of coin.

Solution:

Let the number of dimes be x. So,

Number of nickels = x+4

Number of quarters = 2x

We know that, 1 nickel = $0.05, 1 dime = $0.10 and 1 quarter = $0.25.

Total amount Rachelle has = $4.75.

Subtract both sides by 0.20.

Divide both sides by 0.65.

Now,

Number of dimes = 7

Number of nickels = 7+4 = 11

Number of quarters = 2(7) = 14

Therefore, the number of dimes, nickels and quarters are 7, 11 and 14 respectively.

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