The roof on a house has one side that is in the shape of an isosceles triangle. If the sides of this part are 18 feet long and the angle at the peak is 50°, what is the area of this part of the roof to the nearest tenth of a foot?

124.1 feet

Step-by-step explanation:

An isosceles triangle is one which has two equal sides and two equal angles.

Area of triangle = ab SinC

where a and b are the sides, and C is the given included angle.

From the given question, a = b = 18 feet and C = 50°.

Then,

Area of this part of the roof = x 18 x 18 x Sin 50°

                                                 = x 18 x 18 x 0.7660

                                                = 162 x 0.7660

                                                 = 124.092

The area of this part of the roof is 124.1 feet.

i will pick c put check it over to be sure

step-by-step explanation:

answer: first option i.e. 'a' is correct.

step-by-step explanation:

since we have given that

number of minutes to wrap a small gift box = 4 minutes

we need to find the number of gifts to be wrapped in 5 minutes

since there is a direct variation, as the number of minutes will increase with   number of gifts to be wrapped.

so, let the number of gifts to be wrapped in 5 minutes be x.

so, it becomes,

hence, first option 'a'   is correct.