Mathematics, 03.11.2020 15:50, mvtthewisdead

What is the equation of the parabola shown below, given a focus at F(1, 5) and a directrix of x = −3? In addition, identify the vertex and the equation of the axis of symmetry for the parabola. $x= \frac{1}{8}(y-5)^2-1$ vertex: (−1, 5), axis of symmetry: y = 5 vertex: (5, −1), axis of symmetry: x = −3 vertex: (−2, −5), axis of symmetry: y = 2 vertex: (−1, 5), axis of symmetry: y = 5

$x=\frac{1}{5}(y+5)^2 +2$
$x=\frac{1}{4} (y+2)^2-5$
$x=\frac-{1}{8} (y-5)^2-1$
What is the equation of the parabola shown below, given a focus at F(1, 5) and a directrix of x = −

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What is the equation of the parabola shown below, given a focus at F(1, 5) and a directrix of x = −3...