Mathematics, 03.11.2020 15:40, brodycruce

What is the equation of the parabola shown below, given a focus at F(3, −1) and a directrix of y = 3? In addition, identify the vertex and the equation of the axis of symmetry of the parabola. $y= \frac{1}{8}(x-3)^2 +2$ vertex: (−3, 1), axis of symmetry: x = −1
vertex: (3, 1), axis of symmetry: x = 1
vertex: (3, 1), axis of symmetry: x = 3
vertex: (−3, 1), axis of symmetry: x = 3

$y=\frac{1}{12}(x-3)^2 +1$
$y= -\frac{1}{8}(x-3)^2 +1$
$y=-\frac{1}{4}(x+3)^2 +1$
What is the equation of the parabola shown below, given a focus at F(3, −1) and a directrix of y =

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What is the equation of the parabola shown below, given a focus at F(3, −1) and a directrix of y = 3...