What is the equation of a line that is perpendicular to the line y - 1 = -2 (x + 5) and that passes through the point (-3,2).

Step-by-step explanation:

Write the equation in the form of Y=mX+C so that it is easuer to find the gradientor slope

the slope is -2 .

since we need to find a perpendicular equation, the gradient or slope should be negative reciprocal of the gradient we have now which is -2

the perpendicular gradient = 1/2

coordinates: (-3,2)

y - 2 = (x + 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 1 = - 2(x + 5) ← is in point- slope form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

= - = - =

and (a, b) = (- 3, 2), thus

y - 2 = (x - (- 3) ), that is

y - 2 = (x + 3) ← equation of perpendicular line

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: