A bus has velocity 20 m/s towards east and another bus has velocity 15 m/s in west direction. If they start to move from a point simultaneously, what distances do they cover in 2 minute?

The first bus has covered 2,400 m and the second bus has covered 1,800 m. They are separated by 4,200 m

Step-by-step explanation:

Constant Velocity Motion

A bun has a velocity of 20 m/s towards the east. It means it travels 20 meters each second in that direction. Assuming the east direction is positive, the distance traveled by this bus can be calculated as follows:

X1=20*t

Where t is the time in seconds.

Similarly, the distance traveled by the second bus towards the west is:

X2=-15*t

Note the negative sign because the direction points at the negative reference.

After 2 minutes = 120 seconds have passed, the distance of each bus is

X1= 20*120=2,400 m

X2=-15*120 = 1,800 m

They are separated by 2,400-(-1,800) = 4,200 m

The first bus has covered 2,400 m and the second bus has covered 1,800 m. They are separated by 4,200 m

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8