The polynomial p(x) = x^2+ax+b has distinct roots 2a and b. Find a + b.

Hello,

As 2a and b are two distinct roots of P(x) we can write the following:

Then, a=1/2 and b=-3/2

a+b=1/2-3/2=-1

thanks

Actually, we cannot simplify by b if b is different from 0 so we should take into account the specific case of b=0 but then we come up with a=-2a so a=0 and then 2a=0 et b=0 and this is not possible because it says that 2a and b are two distinct roots, so the case where b=0 is not possible so we can assume that b is different from 0 and then we can simplify b=2ab by 1=2a, so we are good. the solution is a+b=-1

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1

a and c

step-by-step explanation: