Find the derivative of e^ax+b by first principal

ae^ax+b

Step-by-step explanation:

If differentiating something with respect to x, or when finding the derivative on an expression in terms of x

First principal:

f'(x) = lim h → 0, f(x+h)-f(x)/h

f(x+h) = (x+h)^n

f'(x) = lim h → 0, (x+h)^n + x^n / h

Because the power rule states: d/dx[x^n} = nx^n-1.

So, d/dx [e^ax+b] = d/dx[ax+b] × e^ax+b = a × e^ax + b = ae^ax+b

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step-by-step explanation:

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

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