Juan had $24400 and chose to split the money into two different mutual funds. During the first year, Fund A earned 4% interest and Fund B earned 6% interest. If he received a total of $1166 in interest, how much had he invested into each account?

Juan invested $14,900  in Fund A and $9,500 in Fund B.

Step-by-step explanation:

Let x= Amount invested in Fund A .

Since , total amount invested = $24400

Then,  Amount invested in Fund B = 24400-x

Fund A earned 4% interest and Fund B earned 6% interest.

Interest earned by Fund A= 4% of x = 0.04 x

Interest earned by Fund B= 6% of x = 0.06 ( 24400-x)

= 0.06(24400)-0.06x

= 1464-0.06x

Total interest = 0.04x+1464-0.06x= 1464-0.02x

If he received a total of $1166 in interest, then

So, Amount invested in Fund A = $14900

Amount invested in Fund B = $( 24400-14900  ) = $9500

Hence, Juan invested $14,900  in Fund A and $9,500 in Fund B.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

11 feet 6 inches and 8 feet 6 inches