What is the justification for each step in the solution of the equation?
54+2x=5x−3(2+6x)
select from the drop-down menus to correctly justify each step.
−5(4x+6)< −18x+6+4x
- given (example)
−20x−30< −18x+6+4x
combine like terms - distrubutive property - subtraction property of inequality
−20x−30< −14x+6
- addition property of inequality - combine like terms - subtraction property of inequality
−6x−30< 6
- addition property of inequality - division property of inequality - multiplication property of inequality
-6x< 36
- addition property of inequality - multiplication property of inequality - division property of inequality
x> -6
- subtraction property of inequality - division property of inequality - addition property of inequality

Offering 30 if a plus b plus c equals 68 and ab plus bc plus ca equals 1121, where a, b, and c are all prime numbers, find the value of abc. the answer is 1978 but i need an explanation on how to get that.

Astore ordered 750 candles a total wholesale cost of $7910.20. the soy candles cosy $12.17 each and thespecialty candles cost $9.58each. how many of each were bought?

Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.