The derivative of a function f is given by f′(x)=0.1x+e0.25x. At what value of x for x>0 does the line tangent to the graph of f at x have slope 2 ?

X=2.287

Step-by-step explanation:

Since the derivative gives you lines which are tangent to the graph f(x), you can find the slope of the line tangent through the equation of the derivative. Set 2 equal to the derivative and you will get 2=0.1x+e^0.25x (assuming you meant e^0.25x not e*0.25x in your question). Using a graphing calculator in order to find the answer graphically, find at what x are the two equations y=2 and y=0.1x+e^0.25x are equal. The result is x=2.287.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

yes

step-by-step explanation: