Mathematics, 01.11.2020 14:50, PrisonKing3749
The variables x and y satisfy the differential equation dy/dx= (y-1)/(x+1)(x+3) It is given that y = 2 when x = 0.
(i) Solve the differential equation, obtaining y in terms of x.
(ii) Explain why x can only take values that are less than 1
Answers: 1
Mathematics, 21.06.2019 19:20, hahah265
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Mathematics, 21.06.2019 20:30, NetherisIsTheQueen
What is always true about a positive integer raised to a negative odd power?
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Mathematics, 22.06.2019 01:00, tladitidimatso1783
Match the one-to-one functions with their inverse functions.
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The variables x and y satisfy the differential equation dy/dx= (y-1)/(x+1)(x+3) It is given that y =...
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