A rectangle has a length of five inches more than its width it's area is 24 square inches find the dimensions of the rectangle? A. width=3 in length=4 in
B. width=3 in length= 8 in
c. width=4 in length= 5 in
d. width=8 in length =2 in

Width = x

Length = x + 5

Area = 24 square inches

Area = length times width or A = lw for short.

24 = x(x + 5)

24 = x^2 + 5x

x^2 + 5x - 24 = 0

Factor left side.

(x - 3)(x + 5) = 0

Set each factor to 0 and solve for x.

x - 3 = 0

x = 3

x + 5 = 0

x = -5

We must reject x = -5 because we are asked to find the dimensions of the rectangle and dimension cannot be negative.

So, the width is 3 inches and the length is 5 more than 3 inches or 8 inches.

B

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions