SURFACE AREAS AND VOLUMES (10Th Grade) Question
A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter L of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid

here is ur answer

Step-by-step explanation:

6L^2 + πL^2 /4

Step-by-step explanation:

the hemispherical shape is scooped out from one side of the cube, so the total surface area (SA) should include: five surface of cube + one remained side of cube subtracted the circle (r=L/2) + SA of semisphere inner curved.

Or, SA of the remaining solid = cubic SA+ semisphere SA-circle area

= 6L^ 2 + 1/2 * 4π(L/2)^2 - π(L/2)^2

= 6L^2 + (π L^2)/2 -  (πL^2)/4

= 6L^2 +πL^2 /4

6L²+ πL²/4

the balance is found at the link

step-by-step explanation: