One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides of the same square. Find the side of the triangle if the side of the square is 10 ft.

Step-by-step explanation:

Refer to attachment

Let the side of the triangle be a

The line segment x as per Pythagorean is: √(a² - 10²)

Therefore the vertices of the triangle are equidistant from the vertex of the square, so the distance x is same for both vertices

From the triangles we have side of the triangle:

Comparing the two we have:

So the value of a is:

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

this is false ^.^ lol