4xy
4xy
Area of a square with sides being 4xy

Step-by-step explanation:

Answer Text

an equilateral triangle

a right angled triangle

an isosceles triangle

None of these

Answer :

A

Solution :

Acute angle between the lines x2+4xy+y2=0 is tan2(24−1−−−−√)/(1+1)=tan−13–√=tan−1π/3. Angle bisectors of x2+4xy+y2=0 are given by x2−y21−1=xy2

x2−y2=0⇒x=±y

As x+y=0 is perpendicular to x−y=4, so the given triangle is equilateral triangle