Mathematics, 31.10.2020 20:00, sparky1234
A student is asked to calculate the value of 133 using the identity (x + y)3 = x3 + 3x2y + 3xy3 + y3. The student's steps are shown below.
Step 1: 133 = (10 + 3)3
Step 2: = (10)3 + 3(10)2(3) + 3(10)(3)2 + (3)3
Step 3: = (1,000) + (180) + (270) + (27)
Step 4: = 1,477
The correct answer should be 2,197. In which step did the student make his first error?
Answers: 2
Mathematics, 21.06.2019 16:10, rajene9302
On new year's day, the average temperature of a city is 5.7 degrees celsius. but for new year's day 2012, the temperature was 9.8 degrees below the average. i) if a represents the average temperature on new year's day and 7 represents the temperature on new year's day 2012, what formula accurately relates the two values together? ii) what was the temperature on new year's day 2012? dt a 0.8 ii) - 4 1 degrees celsius da-t-98 ii) 59 degrees celsius 1) 7 = -9,8 11) 59 degrees celsius ii) l degrees celsius
Answers: 2
Mathematics, 21.06.2019 19:00, Islandgirl67
What are the solutions of the system? solve by graphing. y = x^2 + 3x + 2 y = 2x + 2
Answers: 1
A student is asked to calculate the value of 133 using the identity (x + y)3 = x3 + 3x2y + 3xy3 + y3...
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