A quantity with an initial value of 870 decays continuously at a rate of 0.75% per day. What is the value of the quantity after 10 weeks, to the nearest hundredth?

10 weeks = 70 days

decay rate = 70 × 0.75% = 52.5%

value = 870 - 52.5% = 413.25

Step-by-step explanation:

^^^

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.