What is an equation of the line that passes through the points (0, -2) and (−5,4)? Put your answer in fully reduced form.

The equation of the line is  y =   x - 2 OR  6x + 5y = -10

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

The rule of the slope of a line is

→ Let us solve the question

∵ The line passes the points (0, -2) and R (-5, 4)

∴ x1 = 0 and y1 = -2

∴ x2 = -5 and y2 = 4

→ Substitute them in the rule of the slope above to find it

∵ m =

∴ m =

Substitute it in the form of the equation above

∴ y =   x + b

∵ b is the y-intercept (value y at x = 0)

∵ At x = 0, y = -2

∴ b = -2

→ Substitute it in the equation

∴ y =   x + (-2)

→ Remember (+)(-) = (-)

∴ y =   x - 2

→ Multiply both side by 5 to cancel the denominator of the fraction

∴ 5y = -6x - 10

→ Add 6x to both sides

∴ 6x + 5y = -6x + 6x - 10

∴ 6x + 5y = -10

∴ The equation of the line is y =   x - 2 OR 6x + 5y = -10

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

2x^2+5x+17

your welcome. : )