Expand the logarithmic expression In(3e^2)

In (3) + 2

Step-by-step explanation:

Expand the logarithmic expression: ln(3e^2)

Multiply --> add logs

ln(3e^2) = ln(3) + ln(e^2)

= ln(3) + 2

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: