What is the correct answer to the following blanks to prove that for all subsets A and B of X, F(A ∩ B) ⊆ F(A) ∩ F(B) given let X and Y be any sets, and let F be any function from X to Y?

In step 2, it's shown that x ∈ A ∩ B, so in step 3, it follows by the definition of set intersection that x ∈ A and x ∈ B.

Then in step 4, by definition of image of an element, both F(x) ∈ F(A) and F(x) ∈ F(B).

The rest of the proof follows.

it is c, trust i got your back lol

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.