What equation is graphed in this figure? y−4=−1/3(x+2) y−3=1/3(x+1) y+2=−3(x−1) y−5=3(x−1) Number graph that ranges from negative ten to ten on the x and y axes. A line passes through begin ordered pair zero comma two end ordered pair and begin ordered pair one comma five end ordered pair

The correct option is 3

Step-by-step explanation:

It is given that the line passes through (-1,4) and (1,-2).

The slope of the line is,

m=\frac{y_2-y_1}{x_2-x_1}

The slope of the given line is,

m=\frac{-2-4}{1-(-1)} =\frac{-6}{2}=-3

The point slope form of a line is,

y-y_1=m(x-x_1)

Where, m is the slope.

Since slope is -3 and point is (-1,4), then the equation of line is,

y-4=-3(x+1)

Since slope is -3 and point is (1,-2), then the equation of line is,

y+2=-3(x-1)

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day

the answer to this is a. a^2 + b^2 = c^2