If daquan had a bag of candy that contains 8 grape candy’s 5 cherry candies 3 lemon candies and 6 lime candies what is the probability that he will select a cherry candy put it back in the bag and select a grape candy

Step-by-step explanation:

First, we have to figure out how many there are all together.

22

so it is going to be

5/22 to get a cherry candy

and to put it back and get a grape is

8/22

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11