The sum of three numbers is 27. The product of the first number times the third number is 56

sum of 3 numbers= 27

a-d+a+a+d=27

=3a=27

a=9

product of numbers=504

=(a-d)a(a+d)=504

=(a^2-d^2)a=504

=[9^2-d^2]9=504

=81-d^2=56

=d^2=81-56

=d^2=25

=d=+-5

If d = 5 series = 4. 9. 14

if d =--5. series = 14 9. 4

95.03 is the answer. hope this !