The half-life of radioactive strontium-90 is 29 years. In 1960, radioactive strontium-90 was released into the atmosphere during testing of nuclear weapons, and was absorbed into people's bones. How many years does it take until only 6% of the original amount absorbed remains?

117.7 years

Step-by-step explanation:

We have half life formula,

A=P

Where ''t'' is number of years

d is half life period.

We know d=29

Where A=6% =0.06

P= 100%=1

Plug in the known values into the formula.

0.06= 1

Divide both sides by 1.

It gives,

0.06=

Take log on both sides

log 0.06= log(0.5)

Divide both sides by log 0.5

4.05889 =

Multiply both sides 29

t =117.7079....

Approximately t= 117.7 years.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0