A restaurant built a ramp to make their facility more accessible to people in wheelchairs. They covered the entire surface of the ramp with metal to make it more durable. How much metal did they use to cover the ramp, including the bottom? Give an exact answer (do not round).

3.41 m² of metal would be needed to cover the ramp

Step-by-step explanation:

The ramp has the shape of a triangular prism.

A triangular prism is a prism that has two equal triangles as base connected by three lateral faces.

The surface area of a triangular prism is the sum of the area of its base and lateral faces.

The surface area = 2B + PH

Where B is the area of the base , H is the height of the prism and P is the perimeter of the triangular base

Hence:

B = 0.5 * 1 m * 0.8 m = 0.4 m²

h = 1 m

P = 1 m + 0.8 m + 0.81 m = 2.61 m

Surface area = 2 * 0.4 m² + 2.61 m × 1 m = 3.41 m²

3.41 m² of metal would be needed to cover the ramp

step-by-step explanation:

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: