The price of Stock A 9 AM was $12.84. Since then, the price has been increasing at the rate of $0.07 each hourAt noon the price of Stock 8 was \$13.34 . To decrease at the rate of $0.09 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?

In 3 hours 7 minutes and 30 seconds both stocks will be same.

Step-by-step explanation:

It is given that the price of Stock A at 9 AM was $12.84. The price has been increasing at the rate of $0.07 each hour.

The price of stock B at noon was $13.34 which is decreasing at the rate of $0.09 per hour.

So, let's set up equation for each.

Price of stock A equation is

y= 0.07 x +12.84

Price of stock B equation is

y= 13.34-0.09 x

Where 'x' is number of hours.

Let's set up both equations as same to find value for x.

0.07 x+12.84= 13.34-0.09 x

Add both sides 0.09 x

0.16 x+12.84= 13.34

Subtract both sides 12.84

0.16 x = 0.5

Divide both sides by 0.16

x=3.125

Let's change the decimal to minutes.

0.125*60= 7.5 minutes

So, in 3 hours 7 minutes and 30 seconds both stocks will be same.

  2087568668/1  

step-by-step explanation:

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)