A box holds a white button, a brown button and a black button. What is the probability of picking a white button then without replacing it, picking a brown button on the second pick?(decimal)

1/5

In decimal = 0.2

Step-by-step explanation:

A box holds a white button, a brown button and a black button.

Hence:

Number of white button= 1

Number of brown button= 1

Number of black button= 1

Total number of buttons = 3

The probability of picking a white button then without replacing it, picking a brown button on the second pick is :

= P(White) × P(Brown) [ without replacement]

= 1/3 × 1/2

= 1/5

In decimal = 0.2

your answer is a

step-by-step explanation:

4*4*4*4=256

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .