Mathematics, 24.05.2020 00:00, aj2869 Franklin needs 1.25 meters of ribbon To wrap each gift. He had a spool of... Franklin needs 1.25 meters of ribbon To wrap each gift. He had a spool of ribbon that contains 25 feet of ribbon that contains 25 feet of ribbon. One meter is equivalent to approximately 3 feet. How many gifts of the same dimension can he wrap using the spool of ribbon

He can wrap 6 gifts using the spool of ribbon

Step-by-step explanation:

Here, we want to know the number of gifts of the same dimension that Franklin can wrap using the spool of ribbon

Per gift 1.25m of ribbon is needed

Now in the spool, there is 25 feet of ribbon

1 m = 3 feet

x m = 25 feet

x = 25/3 meter

so the number of gifts of the same dimension he can wrap using the spool of ribbon will be;

25/3/1.25 = 25/3.75 = 6.67

Since he cannot wrap a gift fractionally, the number of gifts he can wrap is thus 6

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4