The resultant of two forces has magnitude 20 N. One of the forces is of magnitude 20√3 N and makes an angleof 30° with the resultant. Then what is the magnitude ofthe other force?

Magnitude of resultant of two forces (R) = 20 N

Magnitude of first force (A) = 20√3

Angle between A & R = 30°

the magnitude of the other force

Let the magnitude of other force be B.

We know that,

R = √(A² + B² + 2ABcos ∅)

According to the question,

→ B = √(A² + R² + 2ARcos 30°)

cos 30° = √3/2

→ B = √(20√3)² + (20)² + 2 * 20√3 * 20 * √3/2

→ B = √(1200 + 400 + 1200)

→ B = √2800

→ B = √7 * √400

→ B = 20√7 N

Therefore, the magnitude of other force will be 20√7 N.

I hope it will help you.

Regards.

→ B = √(A² + R² + 2ARcos 30°)

cos 30° = √3/2

→ B = √(20√3)² + (20)² + 2 * 20√3 * 20 * √3/2

→ B = √(1200 + 400 + 1200)

→ B = √2800

→ B = √7 * √400

→ B = 20√7 N

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

step-by-step explanation:

goog be able to you with that maybe