Can any kind soul help me please

(i) we will be finding the acceleration here, in the first 20 seconds the velocity was 10

a = velocity/time

a = 10/20

a = 0.5 ms -2

(ii) difference in distance of the bus and bicycle will be given by formula of velocity

velocity of bicycle

10 * 80 = distance

800 metres

velocity of bus

for first 20 seconds( distance= velocity* time)

200 metres

from 20 seconds to 60 seconds, it will be for 40 seconds

then distance will be,

400 metres

final 20 seconds

200 metres

adding the distances of bus it will be 800 metres.

the difference in distance will be 0 metres.

this is wat i think

where r the answers

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."