The average age of residents in a large residential retirement community is 69 years with standard deviation 5.8 years. A simple random sample of 100 residents is to be selected, and the sample mean age Xof these residents is to be computed. The probability that the average age, Xof the 100 residents selected is less than 68.5 years is:

0.194

Step-by-step explanation:

X has a mean of 69 and a standard deviation of 5.8/√100 = 0.58.

The z-score is:

z = (x − μ) / σ

z = (68.5 − 69) / 0.58

z = -0.862

The probability is:

P(Z < -0.862) = 0.194

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )