PLEASE MARK AS BRAINLEST Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-4, -2) B(-2, -2) C(-2, 7) and D(-4, 7).What is the area of rectangle ABCD?

A(-4,-2) B(-2,-2) C(-2, 7) D(-4, 7)

|AB| = √((-2-(-4))^2 + (-2 - (-2))

= √((2)^2 + 0^2) √4

= 2 units

|BC| = √((-2 - (-2))^2 + (7 - (-2))^2

= √5^2 = √25

= 5units.

Let |AB| = The length of the rectangle.

|BC| = The Width of the rectangle.

Hence Area = |AB| × |BC|

Area = 2 × 5 = 10 square units.

4x and 6y

im not sure though

70.30

step-by-step explanation: