The point-slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y-3 = {(x - 1). What is the slope-intercept form of the equation for this line?

Step-by-step explanation:

Just rewrite  y-3 = {(x - 1) as   y-3 = m(x - 1).   {(x - 1)  is not valid.

Next, solve this y-3 = m(x - 1) for y:

Adding 3 to both sides yields    y = m(x - 1) + 3, or:

y = mx - m + 3, or

y = mx + (-m + 3).  This is in slope-intercept form.

If you choose m = 2, then the equation becomes

y = 2x +(-2 + 3), or:

y = 2x + 1

Note:  to get a single answer to this question you must provide the m value.

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !