A turtle is 20 5/6 inches below the surface of a pond. It dives to a depth of 32 1/4 inches. What is the change in the turtle’s position? Write your answer as a mixed number.

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Step-by-step explanation:

the turtle is initially 20 5/6 inches below the surface.

After which he dives to a depth of 32 1/4 inches

then the initial position below - 20 5/6 inch

final position - 32 1/4 inch

the difference in the positions can be calculated taking the difference between initial and final position

this can be done with a simple subtraction of fractions

difference =

when subtracting mixed fractions the whole numbers are first subtracted

 =  

 =

we can now bring the denominators to a common denominator which is 12

then in the first fraction 1/4, denominator is 4 , to bring it to 12 we can multiply the whole fraction by 3

next fraction 5/6 , denominator is 6, to bring it  to 12 we multiply whole fraction by 2

now since  3/12 is smaller than 10/12 so we borrow a whole number from 12 outside the brackets, then

then

= (12 - 1) ()

 = 11

therefore change in turtles position is 11 5/12 inches

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

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step-by-step explanation: