You purchased concentrated cleaner that must be diluted (watered down) before use. Container A is the cleaner, which is a 30% solution. Container B is pure water. You are mixing together the contents of Container A and Container B to produce 60 gallons of 8% solution. How many gallons from each container are needed to create the 60 gallons of 8% cleaning solution? Write your answers as integers only. Container A: 30% Cleaning Solution =
gallons

Container B: Pure Water =
gallons

Container A: 30% Cleaning Solution = 4.8 gallons

Container B: Pure Water = 55.2 gallons

Step-by-step explanation:

since 8% of 60 gallons is 4.8 that means their is 55.2 gallons of pure water

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!