A box is dragged across 202020 meters with a force of 606060 Newtons, which are\dfrac{\text{kg}\cdot\text{m}}{\ text{s}^2} s 2 kg⋅m start fraction, start text, k, g, end text, dot, start text, m, end text, divided by, start text, s, end text, squared, end fraction. What calculation will give us the work done, in Joules (which are \dfrac{\text{kg}\cdot\text{m}^2}{\t ext{s}^2} s 2 kg⋅m 2 start fraction, start text, k, g, end text, dot, start text, m, end text, squared, divided by, start text, s, end text, squared, end fraction)? Choose 1

The work done required to drag box is 1200 Joule.

Work done is defined as the energy transfer that occurs when an object is moved over a distance by an external force .

Where is angle between direction of force and displacement.

Here given that force F = 60 N and Displacement = 20 meters

Since, Displacement of box is in the direction of force.

Therefore, degree.

Substituting all the values.

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1200 Joules

Step-by-step explanation:

Given that:

Distance (d) across which bag is dragged = 20 meters

Applied force (F) = 60 N

The workdone is the product of the applied force and the distance through which the force is applied ;

Hence,

Workdone = Force * Distance

Workdone = 60 N * 20 m

Workdone = 1200Nm

OR 1200 Joules

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .