The contents of seven similar containers of sulfuric acid are 9.8, 10.2, 10.4, 9.8,10.0, 10.2, and 9.6 liters. Find a 95% confidence interval for the mean contents of all such containers, assuming an approximately normal distribution. (Round your answers into two decimal places.)

The 95 confidence interval   is  

Step-by-step explanation:

The sample size is  n  =  7

 The sample data  is  9.8, 10.2, 10.4, 9.8,10.0, 10.2, and 9.6 liters

Generally the sample mean is mathematically represented as

=>          

=>          

Generally the standard deviation is mathematically represented as

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=>    

Note : We are making use of t distribution because n is small i.e n < 30

Generally the degree of freedom is mathematically represented as

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=>    

From the question we are told the confidence level is  95% , hence the level of significance is    

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Generally from the t distribution table the critical value  of   at a degree of freedom of    is  

Generally the margin of error is mathematically represented as  

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=>    

Generally 95% confidence interval is mathematically represented as  

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=>    

17.08

correct me if i am wrong.