The sum of the digits of a two digit number is 13. If 27 is added to the number, the place of the digits are reversed. Then the required number is??

The number is = 10x+y

if reverse the digits, the number is: 10y+x

The sum of its digits is =  x+y=5

I suggest this system of equations:

(10y+x)-(10x+y)=27    ⇒9y-9x=27

x+y=5

We can solve this system of equations by the equalization method

x=5-y

9y-9(5-y)=27

9y-45+9y=27

18y=27+45

18y=72

y=72/18

y=4

x=5-y

x=5-4=1

The number is: 10x+y=10(1)+4=14

the number is 14

this is a very good question

step-by-step explanation:

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y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3