A father is 30 years elder than his son. after 8 years he will be 4 times as old as his son. find their present ages

Father is 30 years older than the son.

After 8 years , he will be 4 times as old as his son.

their present ages

Let the son's age be x and age of father be y years

⟹ Father's age = Son's age + 30

⟹ y = x + 30 -- equation (1)

Also,

Son's age after 8 years = (x + 8) years.

Father's age after 8 years = (y + 8) years.

According to the above condition,

⟹ y + 8 = 4(x + 8)

⟹ y + 8 = 4x + 32

Substitute the value of y from equation (1).

⟹ x + 30 + 8 - 32 = 4x

⟹ 6 = 4x - x

⟹ 6 = 3x

⟹ 6/3 = x

⟹ 2 = x

Substitute the value x in equation (1).

⟹ y = 2 + 30

⟹ y = 32

Therefore,

Son's present age = x = 2 years.

Father's present age = y = 30 years.

I hope it will help you.

Regards.

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x