Write the equation in slope-intercept form of a line that passes through the point (-6, -12) and is perpendicular to y=-2x+5.y=−2x+5.

Step-by-step explanation:

The standard form of equation of a line in slope-intercept form is expressed as:

y =mx+c

m is the slopw

c is intercept

Get the slope of the known line

since y = -2x+5

slope m = -2

Get the slope of unknown line

Since the unknown line is perpendicular to tis line, then

Mm = -1

M = -1/m

M = -1/-2

m = 1/2

Get the intercept of the unknown line:

Substitute the point (-6,12) and m = 1/2 into the equation y = mx+c

12 = 1/2(-6) + c

-12 = -3 + c

c = -12+3

c = -9

Get the equation of the unknown line:

Substitute m = 1/2 and c = -9 into the equation y = mx+c

y = 1/2x -9

2y = x - 18

2y-x = -18

Hence the equation in slope-intercept form of a line that passes through the point (-6, -12) and is perpendicular to y=-2x+5 is 2y-x = 18

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)