Find the slope when give. the following points : (1,6) and (3,-4)

y = -5x + 11

Step-by-step explanation:

Slope (m) =

ΔY

ΔX=

-5

1

=-5

θ =  

arctan(ΔY) + 360°

ΔX

=281.30993247402°

ΔX = 3 – 1 = 2

ΔY = -4 – 6 = -10

Distance (d) = √ΔX2 + ΔY2 = √104 = 10.198039027186

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this